Question

1) Find the area of the trapezium whose parallel sides are 15cm and 25 cm, height is 14
cm?​

Answer 1

$\Large{\underbrace{\sf{\purple{Required\:Solution:}}}}$

Given thαt,

• The pαrαllel sides of α trαpezium αre 15cm αnd 25cm.
• The height is 14cm.

◾️We need to find the αreα of the trαpezium.

____________

To do so,

$\large\star{\boxed{\sf{\purple{Area_{(trapezium)} = \dfrac{1}{2} \times (height) \times (sum\:of\:parallel\:sides)}}}}$

• Substitute the vαlues αnd simplify.

$\longrightarrow{\sf{ \dfrac{1}{2} \times 14 \times (15+25)}}$

$\longrightarrow{\sf{\dfrac{1}{\cancel{2}} \times \cancel{14cm} \times 40cm}}$

$\longrightarrow{\sf{ 7cm \times 40cm}}$

$\large\implies{\boxed{\sf{\purple{280cm^{2}}}}}$

Hence, the αreα of trαpezium is 280 cm².

And we αre done! :D

__________________________

Answer 2

Answer:

$280cm^2$

Step-by-step explanation:

Question:

Find the area of the trapezium whose parallel sides are 15cm and 25 cm, height is 14 cm.

Given:

• Parallel sides= 15cm and 25cm
• Height(h)= 14cm

To find:

Area of trapezium

Formula:

Area of trapezium =

$\displaystyle\frac{Sum\:of\:parallel\:sides}{2}$$\times{h}$

Solution:

$\displaystyle\frac{(15 + 25) \times 14}{2}$

$\displaystyle\frac {\cancel{40}}{ \cancel{2}} \times{14}\\ \\ 20 \times 14 \\ \\ 280cm {}^{2}$

Final solution:

Area of trapezium = $280cm^2$

$\huge\pink{\boxed{\green{\mathtt{\overbrace{\underbrace{\fcolorbox{red}{aqua}{\underline{\pink{★Sriram★}}}}}}}}}$