Math, asked by swarupajohnson, 19 days ago

`1. Find the area of the triangle whose vertices are (0,0),(3,0) and (0,2)​

Answers

Answered by XxItSsMissAayushixX
2

Answer:

Let O(0,0) ,A(3,0) and B(0,2).

On plotting these points O(0,0) is origin , A(3,0) is on x- axis at a distance. of +3

units from origin and B(0,2) is on y-axis at a distance of +2 units from origin.

Thus , BOA is a right angled triangle in which base OA=+3 units and perpendicular

BO =+2 units.

Area of right angled triangle BOA = 1/2. (perpendicular × base) units ^2

= 1/2.(2×3) units ^2.

= 3 units ^2. Answer.

Second- method:-

Area of triangle= 1/2[x1.(y2-y3)+x2.(y3-y1)+x3.(y1-y2)] units ^2.

=1/2[0.(0–2)+3.(2–0)+0.(0–0)] units ^2.

= 1/2.[ 6 ] units ^2.

= 3 units ^2. Answer.

hope \: it \: helps \: you

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