Question

1. Find the area of triangular region with vertices given below. (8,9) (2,6) and (9,2)​

Answer 1

Answer:

Area of triangle is given by formula

Area = × [x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2)]

Where (x1, y1), (x2, y2) and (x3, y3) are vertices of triangle

Here,

(x1, y1) is (8, 9)

⇒ x1 = 8 and y1 = 9

(x2, y2) is (2, 6)

⇒ x2 = 2 and y2 = 6

(x3, y3) is (9, 2)

⇒ x3 = 9 and y3 = 2

Hence substituting values in formula for area we get

Area = × [8(6 – 2) + 2(2 – 9) + 9(9 – 6)]

Area = × [32 + (-14) + 27]

Area = × [32 + 13]

Area = × 45

Area = 22.5 unit2

Step-by-step explanation:

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Answer 2

Answer:

Coordinates are (8,9) (2,6) (9,2)

Area =

$\frac{1}{2} ( \: 8(6 - 2) + 2(2 - 9) + 9(9 - 6))$

$= \frac{1}{2} (32 - 14 + 27)$

$= \frac{1}{2}(45)$

$= 22.5 \: {unit}^{2}$

If the area comes negative we take its positive value(mod)

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