Question

1. Find the breadth of a rectangular park, if its area is 660 sq m. and the
length is 30 cm. Also find the cost of the fencing around it at the rate of 150
rupees per sq. m.​

Answer 1

Answer:

Let breadth be - x

$\color{black}\boxed{\colorbox{saffron}{Area - length×breadth}}$

${660}^{2} = {30}^{2} \times {x}^{2} \\ \\ = 435600 = 900 \times {x}^{2} \\ \\ = 435600 \div 900 = {x}^{2} \\ \\ = {x}^{2} = 484 \\ \\ = x = {22}^{2} \\ \\ = x = 22cm$

So, breadth-22 m

Step-by-step explanation:

$\color{black}\boxed{\colorbox{saffron}{Perimeter-2(length+breadth)}}$

= 2(30+22)

= 2×52

= 104 m

Cost of fencing - 104×150= Rs. 15600

Answer 2

Answer:99000

Step-by-step explanation:

Breadth = 660/30 =22

Now, cost = 660 *150 = rupees 99000