Math, asked by hafsanapatel, 4 months ago


1. Find the cost of covering a wall of dimension 12 mx7m with tiles of dimension 3 mx 2m
at the rate of ruppes16 pertile,​

Answers

Answered by naveenauday
2
Area of wall= 12x7=84m^2
Area of tile=3x2=6m^2
No of tiles required=
area of wall/area of tile
=84/6=14
Cost of a tile. =₹16
Total cost for covering the wall=14x16=₹224
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