Question

1):Find the cost of fencing a rectangular park of length 250m and Breadth 175 m at rate of ₹12 per meter.
2) Pinky runs around a square field of side 75m and Bob runs around a rectangular field with length 160m and breadth 105m who covers more distance??
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Answer 1

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1) Length of the park=250m

Breadth of the park=175m

Perimeter=2(250+175)

=2×425

=850m

Cost of fencing =12×850

=₹10200

2) Given: Side of the square field measure 75m, length of the rectangular field is 160m and the breadth is 105m.

To find: Whether Pinky or Bob ran more distance and the difference.

Answer:

Since it's given that they ran around the field, we will have to calculate the perimeter.

Perimeter of the Square field:

Formula: 4 x Side.

Substituting the value in the formula,

Perimeter = 4 x 75

Perimeter = 300m

Therefore, Pinky ran a distance of 300m.

Perimeter of the Rectangular field:

Formula: 2(Length + Breadth)

Substituting the values in the formula,

Perimeter = 2(160 + 105)

Perimeter = 2 x 265

Perimeter = 530m

Therefore, Bob ran a distance of 530m.

Now in comparison, Bob ran more distance.

By how much ⇒ The difference.

530 - 300 = 230m.

Therefore, Bob ran more distance than Pinky by 230m.

Hope it helps :)

Answer 2

➥Question

• Find the cost of fencing a rectangular park of length 250m and Breadth 175 m at rate of ₹12 per meter.

➥Answer

Length of the rectangular park = 250 m

Breadth of the rectangular park = 175 m

To calculate the cost of fencing we require perimeter.

$\large{\boxed{\underline{\mathrm{Perimeter\:of\:the\:rectangle\:=2×(L\:+B)}}}}$

$\large \mathrm 2 \times (250m \: + \: 175m) \\ 2 \times (425m) = 850m$

Cost of fencing 1m of park = ₹12

Therefore, the total cost of fencing the park

$\large= \:₹12 \times 850 = \: ₹10200$

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➥Question

• Pinky runs around a square field of side 75m and Bob runs around a rectangular field with length 160m and breadth 105m who covers more distance??

➥Answer

Distance covered by Pinky in one round = Perimeter of square

$\large{\boxed{\underline{\mathrm{Perimeter\:of\:square\:=4×Length\:of\:1\:side}}}}$

$= 4 \: \times \: length \: of \: a \: side \\ = 4 \times 75m = 300m$

DISTANCE COVERED BY PINKY = 300m

Distance covered by Bob in one round = Perimeter of rectangle

$\large{\boxed{\underline{\mathrm{Perimeter\:of\:rectangle\:=2×(L+B)}}}}$

$= 2 \times (l + b) \\ = 2 \times (160m + 105m) \\ 2 \times 265m = 530m$

DISTANCE COVERED BY BOB = 530m

Diffrence in the distance covered = 530m – 300m = 230m

Therefore, bob covers more distance by 230m.