Question

1. Find the cube of:
(i) 3a - 26​

Answer 1

Answer:

Step-by-step explanation:

Hi ,

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We know the algebraic identity,

( x - y )³ = x³ - 3x²y + 3xy² - y³

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Now ,

x = 3a , y = 2b

( 3a - 2b )³

= (3a)³-3×(3a)²×2b+ 3×3a×(2b)²-(2b)³

= 27a³ - 54a²b + 36ab² - 8b³

I hope this helps you.

: )

Answer 2

Answer:

Hi your answer is as follows

Step-by-step explanation:

$We~know~that~(a-b)^3=a^3-b^3-3ab(a-b)\\\\(3a-26)^3=27a^3-17576-3*3a*26(3a-26)\\\\=27a^3-17576-234a(3a-26)\\\\=27a^3-17576-702a^2+6084a$

Mark as brainliest if you are satisfied with my answer.