Question

1. Find the cubes of:
(i) x + 3​

Answer 1

(x+3)³

x³ + 3(x)(3)(x+ 3) + 3³

x³+9x(x+3)+27

x³+9x²+27x+27

Answer 2

Answer:

x^3+9x^2+27x+27

Explanation:

(x+3)^3

(x+3)(x+3)(x+3)

x^2+3x+3x+9(x+3)

x^3+3x^2+6x^2+18x+9x+27

= x^3+9x^2+27x+27 answer