Question

1. Find the cubes of the following expression

a) (x +2)​

Answer 1

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$(a+b)^3$ =$a^3+b^3+3a^2b+3ab^2$

$(x+2)^3$ = $x^3+2^3+3*x^2*2+3*x*2^2$

                 $2^2=4$

                $2^3=8$

              = $x^3+8+6x^2+3*x*4$

                            = $x^3+8+6x^2+12x$

$(x+2)^3$ = $x^3+8+6x^2+12x$ $is \:your\:final\:answer$

Answer 2

Answer:

${(a + b)}^{3 \:} \: = {a}^{3} + 3 {a}^{2} b \: + \: 3a {b}^{2} + b \\ {b}^{3}$

$so \: for {(x + 2)}^{3} = {x}^{3} + 3 {x}^{2}2 + 3x {2 }^{2} + {2}^{3} \\ = {x}^{3} + 6 {x}^{2} + 12x + 8$