Question

1. Find the derivative of the given functions.
(a) y=tan^-1_√x​

Answer 1

$\huge\fcolorbox{black}{lime}{AnsweR:}$

y = tan^-1(√x,)

tan^-1x=y,

dy/dx=1/1+(x)^2,

dy/dx= 1/1+(√x)^2,

dy/dx=1/1+(√x)(√x),

dy/dx= 1/1+x.

So, derivative function of y = 1/1+x!.

$\large\bold{\bigstar\:Mimansa\:here\:\bigstar!}$

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