Question

1. Find the distance between points P(-7, – 4) and
Q(-2, 8).​

Answer 1

Step-by-step explanation:

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Answer 2

GiveN:-

• P(-7, -4)
• Q(-2, 8)

To FinD:-

The distance between P and Q.

SolutioN:-

We know that,

$\large{\green{\underline{\boxed{\bf{Distance=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}}}}}}$

where,

• x1, y1 are coordinates of first point
• x2, y2 are coordinates of second point
• x1 = -7
• x2 = -2
• y1 = -4
• y2 = 8

Putting the values,

$\large\implies{\sf{Distance=\sqrt{((-2)-(-7))^2+(8-(-4))^2}}}$

$\large\implies{\sf{Distance=\sqrt{(-2+7)^2+(8+4)^2}}}$

$\large\implies{\sf{Distance=\sqrt{(5)^2+(12)^2}}}$

$\large\implies{\sf{Distance=\sqrt{25+144}}}$

$\large\implies{\sf{Distance=\sqrt{169}}}$

$\large\therefore\boxed{\bf{Distance=\frac{+}{-}13\:units.}}$

The distance between points P and Q is 13 units.