Question

1.
Find the distance between the following pairs of
points.

iii) (a cosα, a sinα), (a cosβ, a sinβ)
​

Answer 1

the distance between A (x1,y1) and B (x2,y2)
= √(x2-x1)² +(y2-y1)²

here A (a cos α, a sin β) = (x1,y1)
B(a cosβ, a sin α) = (x2,y2)

AB = √(acos β - a cos α)² + ( a sin α - a sin β)²

=√a²cos² β + a² cos² α -2a² cosαcosβ +a²sin²α + a² sin² β - 2a² sin α sin β

= √a²(cos²β +sin² β) + a²(cos² α +sin² α) -2a²(cosαcosβ+sinαsinβ)
= √a²+a² -2a² cos(α-β)
= √2a² -2a² cos(α-β)
= √2a²[1-cos(α-β)]
=a √2[1-cos(α-β)]



Hope it helps...
Please mark my answer as the brainliest...

Answer 2

Step-by-step explanation:

Sorry don't know the answer