Question

1. Find the distance between the following pairs of points :
(i) (-3, 6) and (2,-6)
(ii) (-a, -b) and (a, b)

2 . Find the distance between the origin and the point : (i) (-8, 6) (ii) (-5, -12) (iii) (8, -15)​

Answer 1

Answer:

(i) -3 -2 -1 0 1 2 3 4 5 6

so, there are the-2 -1 0 1 2 3 4 5 are distence.

2 1 0 -1 -2 -3 -4 -5 -6

so, there are the 1 0 -1 -2 -3 -4 -5 are the distence.

Step-by-step explanation:

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Answer 2

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1). i) The formula used is square root {(x1-x2)²2+(y1-y2)²2}

so answer would be square root

{(-3-2)²2+(6-6)²2}

that is 5

ii). Let A (a,b)=(x,y) and B (-a,-b)=(x2,y2) be the points a straight line

AB=√(x2-x1)²+(y2-y1)²

AB= √(-a-a)²+(-b-b)²

=√(-2a)²+(-2b)²

=√4a²+4b²

=2√a²+b² units