1. find the equation of set of all points whose distance from (0,4) are 2/3 of their distance from the line y=9.
2.find the number of 5 digit telephone numbers having atleast one of the digit repeated.
3.how many four-letter words can be formed using the letter of the word 'INEFFECTIVE'.
4.R is the relation on the set of natural numbers N defined by a R b<=>a/b is an integral power of
a) is (a,a) belongs to R, for all a belonging to N.
b) (a,b) belongs to R => (b,a) belongs to R
c) (a,b) belongs to R, (b,c) belongs to R => (a.c) belongs to R.
sir please help us with these questions because our exam is on 25th February.
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1. P(x1,y1)
(distance from (0,4) )² = (2/3)² (distance from y=0 )²
x1² + (y1 - 4)² = 4/9 * (y1 - 9)²
9 x1² + 9 y1² -9* 8 y1 + 9*16 = 4 y1² - 4* 18 y1 + 4* 81
9 x² + 5 y² - 180 = 0 replace (x1, y1) by (x,y)
It is an ellipse
2. 5 digit tel numbers : a b c d e
b,c,d,e digits can be from 0 to 9. a cannot be 0.
Let us choose a digit for a, then for b, then for c and so on....
Number of 5 digit numbers with no repetitions at all = 9 * 9 * 8 * 7 * 6
= 27216 or 9 * C(9, 5)
Total number of 5 digit numbers abcde: 9* 10*10*10*10 = 90, 000
Number of numbers having at least one digit repeated =
90, 000 - 27, 216 = 62, 784
3)
Distinct letters of the word: INEFFECTIVE: I, N, E, F, C, T, V,
Number of 4 letter words: P(7, 4) = 7!/3! = 7*6*5*4 = 840
(assuming that each letter could be used only once).
If each letter could be used any number of times, then: 7⁴
4)
a R b < = > a/b is an integer
(a , a) belongs to R as a/a = 1 (an integer): TRUE
Let a R b, a≠b , then a/b = integer, then b/a is not an integer. so (b,a) ∉ R
False.
(a, b) ∈ R, and (b ,c) ∈ R. So a/b is integer and b/c is an integer.
hence, a/b * b/c = a/c is an integer.
hence, (a, c) ∈ R TRUE
(distance from (0,4) )² = (2/3)² (distance from y=0 )²
x1² + (y1 - 4)² = 4/9 * (y1 - 9)²
9 x1² + 9 y1² -9* 8 y1 + 9*16 = 4 y1² - 4* 18 y1 + 4* 81
9 x² + 5 y² - 180 = 0 replace (x1, y1) by (x,y)
It is an ellipse
2. 5 digit tel numbers : a b c d e
b,c,d,e digits can be from 0 to 9. a cannot be 0.
Let us choose a digit for a, then for b, then for c and so on....
Number of 5 digit numbers with no repetitions at all = 9 * 9 * 8 * 7 * 6
= 27216 or 9 * C(9, 5)
Total number of 5 digit numbers abcde: 9* 10*10*10*10 = 90, 000
Number of numbers having at least one digit repeated =
90, 000 - 27, 216 = 62, 784
3)
Distinct letters of the word: INEFFECTIVE: I, N, E, F, C, T, V,
Number of 4 letter words: P(7, 4) = 7!/3! = 7*6*5*4 = 840
(assuming that each letter could be used only once).
If each letter could be used any number of times, then: 7⁴
4)
a R b < = > a/b is an integer
(a , a) belongs to R as a/a = 1 (an integer): TRUE
Let a R b, a≠b , then a/b = integer, then b/a is not an integer. so (b,a) ∉ R
False.
(a, b) ∈ R, and (b ,c) ∈ R. So a/b is integer and b/c is an integer.
hence, a/b * b/c = a/c is an integer.
hence, (a, c) ∈ R TRUE
kvnmurty:
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