Question

1. Find the equation of the circle concentric
...(x2+ y2 - 4x - 6y - 3 = 0 and which touches the y-axis.
with
the
circie​

Answer 1

Answer:

x^2 + y^2 - 4x - 6y + 9 = 0

Step-by-step explanation:

x^2+ y^2- 4x -6y-3 = 0

touches y-axis

then eq^n of circle

(x-h)^2 + (y-k)^2 = h^2

2g = -4 , g= -2

2f = -6 , f= -3

centre of circle

(-g , -f) ,(2, 3)

touches y axis

then centre of circle is (h,k) = (2,3) eq^n (x-h)^2 + (y-k)^2 = h^2

(x-2)^2 + (y-3)^2 = 2^2

x^2 - 4x +4 +y^2 - 6y + 9 = 4

x^2 + y^2 - 4x - 6y +9 = 0

final ans x^2+y^2-4x-6y+9=0

Answer 2

Answer:

Step-by-step explanation: