Question

1. Find the equation of the circle whose centre is (-1,2) and which passes through (5,6)​

Answer 1

Answer:

Step-by-step explanation:

So if the circle passes through (5,6) it means, it lies on the circle.

Therefore, the dist between (5,6) to centre = radius

So radius = $\sqrt{52}$ (By using distance formula)

Now, equation of circle with centre (h,k)

=> $(x-h)^{2} + (y-k)^{2} = r^{2}$

So, plugging in the values, we get,

$(x+1)^{2} + (y-2)^{2} = 52$