Question

1.Find the equation of the line passing through (1,2) and parallel to 3x+5y=3.​

Answer 1

Answer:

The equation of line parallel to 3x+5y+7=0 is 3x+5y+k=0

The required line passes through (1,2)

So 3(1)+5(2)+k=0

3+10+k=0

13+k=0

k=−13

So the required line is 3x+5y−13=0

Answer 2

Answer:

The equation of line parallel to 3x+5y+7=0 is 3x+5y+k=0

The required line passes through (1,2)

So 3(1)+5(2)+k=0

3+10+k=0

13+k=0

k=−13

So the required line is 3x+5y−13=0