1) Find the equation of the line which passes through the point of intersection of lines x+2y+6=0 2x-y=2 & which makes intereept 5 on Y axis.
Answers
Answered by
1
Answer:
Step-by-step explanation:
k
(
7
x
−
3
y
−
19
)
+
(
3
x
+
2
y
+
5
)
=
0
⇒
(
7
k
+
3
)
x
+
(
2
−
3
k
)
y
+
(
5
−
19
k
)
=
0
.
.
[
1
]
If the straight be parallel to the straight line
2
x
−
y
+
1
=
0
then
7
k
+
3
2
=
2
−
3
k
−
1
⇒
7
k
+
3
=
−
4
+
6
k
⇒
k
=
−
7
Inserting the value of k in [1]
(
7
⋅
(
−
7
)
+
3
)
x
+
(
2
−
3
⋅
(
−
7
)
)
y
+
(
5
−
19
⋅
(
−
7
)
)
=
0
⇒
−
46
x
+
23
y
+
138
=
0
⇒
2
x
−
y
−
6
=
0
This is the equation of the required straight line.
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