Question

1. Find the equation of the lines passing through the point (1,1) tercept - i slope 3 and-2.3 and the perpendicular from the origin makes an angle 60° with x-axis

jaan ​

Answer 1

Answer:

this is my answer

Explanation:

i) Given y intercept = – 4, Let x intercept be a Now equation of the lines is x/a + y/-4 = 1. It passes through (1,1) (ii) Slope m = 3, passing through (x1, y1) = (1, 1) Equation of the line is y – y1 = m(x – x1) (i.e) y - 1 = 3(x – 1) ⇒ y – 1 = 3x – 3 ⇒ 3x – y = 2 (iii) Passing through (1, 1) and (-2, 3) Equation of the line passing through 2 points is (iv) P = Distance between (0,0) and (1,1) ← Prev QuestionRead more on Sarthaks.com - https://www.sarthaks.com/917227/find-the-equation-of-the-lines-passing-through-the-point-with-intercept-with-slope-iii-and