Question

1) find the equation of the passing through the point (3,-4) and (7,10)​

Answer 1

Solution
Slope of the given line=slope of AB=4−7−2−3=35
4
-
7
-
2
-
3
=
3
5
, Thus, m=35
=
3
5

∴
∴
required equation is y+5x−4=35⇔3x−5y−37=0
y
+
5
x
-
4
=
3
5
⇔
3
x
-
5
y
-
37
=
0
.

Answer 2

Answer:

》》》》》》》》》》

We first find the slope m of the line passing through the points (3,4) and (−1,0) (x-intercept).

The slope of the line is:

m=

x−x

1

​

y−y

1

​

​

=

3−(−1)

4−0

​

=

4

4

​

=1

Point-Slope Formula:

y−y

1

​

=m(x−x

1

​

) where m is the slope and (x

1

​

,y

1

​

) is the given point.

Now substituting the values:

y−0=1(x−(−1))

⇒y=x+1

Hence, the equation of the line is y=x+1.