Question

1. Find the equation of the straight line which passes through the point (2,-3) and the point of intersect of the lines x + y + 4 = 0 and 3x - y - 8 = 0.

No copy sopy.....xD
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Answer 1

$Answer⬇️$

$x + y = 4 \\ 3x - y = 8$

So,we find the value of x=1 and y=5 from those eq

so, the coordinates are (1,-5)

$x - \frac{1}{2} - 1 = y - \frac{( - 5)}{ - 3} (- 5 ) \\ x - 1 = y + \frac{5}{2} \\ 2x - 2 = y + 5 \\ 2x - y - 7 = 0$

⬆️ Here is Your Answer⬆️

Answer 2

Answer:

Any line through the intersection of the lines x+y+4=0 and 3x−y−8=0 has the equation :

(x+y+4)+λ(3x−y−8)=0

This will pass through (2,−3) if

(2−3+4)+λ(6+3−8)=0

3+λ=0

λ=−3

Putting the value of λ, we get the equation of the required line as 2x−y−7=0..

here is ur answer siso...

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