Question

1) Find the
from the
energy
needed
to remove a neutron from the nucleus of
the Calcium istopes
42
ca,
20.

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Answer 1

Answer:

ca is the best for you I hope you have satisfied with the answer

Answer 2

Answer:

4220Ca is 0.012321u. S0, the binding energy of the missing neutron is (0.012321u)(931.49MeVu)=11.5MeV.