Math, asked by deathstrang3, 1 month ago

(1) Find the greatest number which divisible 691 and 1483 leaving remainder 7 in each case.

(2)find the smallest number which when divided by 15, 20 and 48 will each case leave 7 as the remainder.

please give all the answers. please

Answers

Answered by krishnendu212

0

Answer:

1) 18

2) 249

Step-by-step explanation:

hope it help you

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