Math, asked by deathstrang3, 1 month ago

(1) Find the greatest number which divisible 691 and 1483 leaving remainder 7 in each case.

(2)find the smallest number which when divided by 15, 20 and 48 will each case leave 7 as the remainder.

please give all the answers and correct answers. please.​

Answers

Answered by ajaymunjal208
0

Step-by-step explanation:

I think

2nd question's answer is 8

Please mark me as brainliest

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