Math, asked by thedopest1721, 17 days ago

1. Find the H.C.F of the following. I. 2 +2,2 − 4,2 +3+2 II. (+)2,2 − 2,22 + −2 III. 4−20,2 −25, 2 −3−20

Answers

Answered by jhansism492
0

Answer:

24(6x

4

−x

3

−2x

2

)

=2

3

×3×x

2

(6x

2

−x−2)

=2

3

×3×x

2

(3x−2)(2x+1)

=20(2x

6

+3x

5

+x

4

)=20x

4

(2x

2

+3x+1)

=2

2

×5×x

4

(x+1)(2x+1)

HCF of the two expression is

=2

2

x

2

(2x+1)=4x

2

(2x+1)

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