Question

1. Find the HCF of 160, 165 and 305
(a) 4
(b)5
(C) 3
(d) 6​

Answer 1

AnsWer :

B ) 5.

Solution :

Let us,

• N1 = 160.
• N2 = 165.
• N3 = 305.

Prime factorization of N1.

$\begin{array}{r | l} 2 & 160 \\ \cline{2-2} 2 & 80 \\ \cline{2-2} 2 & 40 \\ \cline{2-2} 2 & 20 \\ \cline{2-2} 2 & 10 \\ \cline{2-2} 5 & 5 \\ \cline{2-2} & 1 \end{array}$

Prime factorization of N2.

$\begin{array}{r | l} 3 & 165 \\ \cline{2-2} 11 & 55 \\ \cline{2-2} 5 & 5 \\ \cline{2-2} & 1 \end{array}$

Prime factorization of N3.

$\begin{array}{r | l} 5 & 305 \\ \cline{2-2} 61 & 61 \\ \cline{2-2} & 1\end{array}$

$\rule{50}1$

Now,

Taking Common No in ( N1 , N2 and N3 )

$\tt\dagger \: \: \: \: \: 160\leadsto 2 \times 2 \times 2 \times 2 \times 2 \times 5.$

$\tt\dagger \: \: \: \: \: 165\leadsto3 \times 5 \times 11.$

$\tt\dagger \: \: \: \: \: 305\leadsto5 \times 61.$

HCF ( N1 , N2 and N3 ) = 5.

Therefore, HCF of given no be 5.

Answer 2

Step-by-step explanation:

5 is the answer of your questions