Question

1) Find the HCF of the following by prime - factorisation and by continued division method.
(i) 48, 64
(ii) 126, 216 (iii) 40, 60, 56 (iv) 10, 35, 40​

Answer 1

Answer:

Step 1: Divide the largest number by the smallest number. Step 2: Take divisor as new dividend and remainder as the new divisor, i.e. divide the first divisor by the first remainder. Step 3: Proceed till the remainder is zero and the last divisor will be the HCF of the given numbers. Therefore, HCF of 24 and 15 is 3