1.
Find the HCF of the following numbers by prime factorisation and continued division
method?
i 18, 27, 36
ii. 106, 159, 265
fii
. 10, 35, 40
iv. 32, 64, 96, 128
Answers
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5
Answer:
A...
3^2×2,3^3,3^2×2^2
HCF=2×3^2
B..
2×53,×3×53,×5×53
=HCF=53
C..
5×2,5×7,2^3×5
HCF=5
D..
2^5,2^6,2^5×3,2^7
HCF=2^5
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