Question

1. Find the HCF of the given numbers by prime factorisation method: (i) 105, 140, 175

Answer 1

Answer:

Prime factors of 105 = 3 × 5 × 7

Prime factors of 140 = 2 × 2 × 5 × 7

Prime factors of 175 = 5 × 5 × 7

Notice that 5 occurs as a common prime factor at least factor one time and 7 one time in given numbers.

Therefore HCF of 105, 140 and 175 is: 5 × 7 = 35