1. Find the HCF of the given polynomials:
(1) 14pq, 28p292
(ii) Babc, 24ab2, 12025
Answers
Answered by
10
1) HCF 14, 28 = 14
HCF 14pq , 28p²q² = 14pq
.....
.
Answered by
6
Answer:
Ohhhhh...... hello!!!
Aap ki aur koi gf Nahi hai kya????
Similar questions