Question

1. Find the HCF of the given polynomials:
(1) 14pq, 28p292
(ii) Babc, 24ab2, 12025​

Answer 1

1) HCF 14, 28 = 14

HCF 14pq , 28p²q² = 14pq

.....

.

Answer 2

Answer:

Ohhhhh...... hello!!!

Aap ki aur koi gf Nahi hai kya????