1) Find the HCF of the numbers 40 and 56 by division method.
Answers
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The H.C.F. of the numbers 40 and 56 is 8.
Given:-
The numbers 40 and 56 are given.
To Find:-
HCF of numbers 40 and 56.
Solution:-
To find the HCF by division method we first divide the larger number by the smaller number
between 56 and 40, 56 is larger so we divide it by 40
Using Euclid's Division Lemma
Dividend= Divisor*Quotient+ Remainder
56= 40×1+16
Step2 Next, we divide the divisor by the remainder of the previous division and repeat this same procedure till the remainder becomes zero. The divisor which does not leave a remainder is the H.C.F of the numbers
Dividing 40 by 16
40= 16×2+8
Dividing 16 by 8
16= 8×2+0
Dividing by 8 does not leave a remainder. So, 8 is the H.C.F.
Hence, H.C.F. of 40 and 56 is 8.
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