1. Find the HCF of the numbers in each set.
(a) 28,36 (b) 45, 60 (c) 70, 71 (d) 35, 49 (e) 24,48
(f) 60,100 (g) 78,98 (h) 30,40 and 80 (1) 21,23 and 27
Answers
Answer:
Solution:
(a) Factors of 18 = 2 x 3 x 3 (b) Factors of 30 = 2 x 3 x 5
Factors of 48 = 2 x 2 x 2 x 2 x 3 Factors of 42 = 2 x 3 x 7
H.C.F. (18, 48) = 2 x 3 = 6 H.C.F. (30, 42) = 2 x 3 = 6
(c) Factors of 18 = 2 x 3 x 3 (d) Factors of 27 = 3 x 3 x 3
Factors of 60 = 2 x 2 x 3 x 5 Factors of 63 = 3 x 3 x 7
H.C.F. (18, 60) = 2 x 3 = 6 H.C.F. (27, 63) = 3 x 3 = 9
(e) Factors of 36 = 2 x 2 x 3 x 3 (f) Factors of 34 = 2 x 17
Factors of 84 = 2 x 2 x 3 x 7 Factors of 102 = 2 x 3 x 17
H.C.F. (36, 84) = 2 x 2 x 3 = 12 H.C.F. (34, 102) = 2 x 17 = 34
(g) Factors of 70 = 2 x 5 x 7 (h) Factors of 91 = 7 x 13
Factors of 105 = 3 x 5 x 7 Factors of 112 = 2 x 2 x 2 x 2 x 7
Factors of 175 = 5 x 5 x 7 Factors of 49 = 7 x 7
H.C.F. = 5 x 7 = 35 H.C.F. = 1 x 7 = 7
(i) Factors of 18 = 2 x 3 x 3 (j) Factors of 12 = 2 x 2 x 3
Factors of 54 = 2 x 3 x 3 x 3 Factors of 45 = 3 x 3 x 5
Factors of 81 = 3 x 3 x 3 x 3 Factors of 75 = 3 x 5 x 5
H.C.F. = 3 x 3 = 9 H.C.F. = 1 x 3 = 3
Step-by-step explanation: