Question

1. Find the HCF of two consecutive:
(1) even numbers
(2)odd numbers
​

Answer 1

Answer:

H. C. F. of any two consecutive even numbers = 2

Step-by-step explanation:

Let 2n,(2n+2) are two consecutive even Numbers.

2n = 2×n

2n+2 = 2(n+2) = 2×(n+2)

HCF(2n,2n+2)= 2

/* Product of the smallest power of each common prime factors of the numbers

Therefore,

H. C. F. of any two consecutive even numbers = 2

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