Question

1) Find the height of a triangle whose area is 24a² square units and base is 8a units.
2)Find the value of P if
441-p²=(21)²-(17)²

Answer 1

area of triangle is 1/2×b×h
24a^2=1/2×8a×h
h=6a

Answer 2

Answer:

1) h = 6a    2) p = 17

Step-by-step explanation:

1)

$\frac{1}{2} bh = 24\\\\\frac{1}{2} (8a)(h) = 24\\\\4ah = 24a^2\\\\h = \frac{24a^2}{4a} \\\\h = 6a$

2)

441 - p² = (21)² - (17)²

441 - p² = (21 + 17)(21 - 17)  [a² - b² = (a + b)(a - b)]

441 - p² = (38)(4)

441 - p² =152

441 - 152 = p²

289 = p²

√289 = p²

17 = p