Math, asked by mamtasinha324, 7 months ago

1. Find the interest in the following problems :
(i) Principal = 500; Rate = 8% per annum; Time = 3 years.
(ii) Principal = 800; Rate = 1.5% per month; Time = 1.3 years.
(i) Principal = 400; Rate = 20 paise per rupee per annum; Time = 6 months.
(iv) Principal = 300; Rate = 12% per annum; Time = 8 months.

Find also the amount in each case.

please give me answer in easy way........

give me right solution and fast answer...

fast fast....​

Answers

Answered by mohitssrw
7

Answer:

Step-by-step explanation:

1.

principal = 500

rate          = 8%

time         = 3 yrs

S.I.   =  p * t  * r/100    = 500 * 8 * 3/100 =   120

amount = S.I + principal  = 500 +120  = 620

2.

principal = 800

rate             = 1.5 %

time         =1.3 yrs

S.I. = p * t * r/100   = 800 * 1.5 * 1.3 /100   = 306/10 = 30.6

amount = S.I + principal = 800 + 30.6 = 830.6

3.

principal = 400

rate             = 20 paisa = 20/100  = 1/5

time         = 6 month

S.I. = p * t* r /100  = 400 * 6 * 1/ 5 * 100 =   24/5 = 4.8

amount = S.I + principal = 400 + 4.8  = 404.8

4.

principal = 300

rate             = 12 %

time         = 8 month

S.I. = p * t * r /100  = 300 * 12 * 8 /  100   = 36 * 8 = 288

amount = S.I + principal = 300 + 288 = 588

hope it helps you very well

Answered by anjanag1010
2

Answer:

187.2

Step-by-step explanation:

aP=500

R=8%

T=3yr

solve 500*8*3/100=120

b P=800

R=1.5

T=1.3yr

solve

R=1.5%per month

(1.5*12) =18%per year

T=1.3

800*18*1.3/100=187.2

Ans=187.2

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