Math, asked by majjidasrath, 1 year ago

1)find the interest on rupees 1300 @ 5% per annum for 146 days.

2)Harry borrowed rupees 450 from his friend at 6% per annum he returned the amount after 8 months how much money did he pay?

Answers

Answered by BloomingBud
38
1) Find the interest on ₹ 1300 at the rate of 5% per annum for 146 days.

\mathbb{SOLUTION}:

Principal (P) = ₹ 1300
Rate of interest (R) = 5% per annum
Time (T) = 146 days

146 days = \frac{146}{365} = \frac{2}{5} year

To be found : \bf{Simple \:Interest (S.I)}

We know that,

S.I = \frac{P \times R \times T}{100} \\ \\ S.I= \frac{1300 \times 5 \times \frac{2}{5} }{100} \\ \\ S.I= \frac{1300 \times 5 \times 2}{100 \times 5} \\ \\ S.I= 26

Hence, Simple Interest (S.I) = ₹ 26.

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2)Harry borrowed ₹ 450 from his friend at 6% per annum. He returned the amount after 8 months. How much money did he pay?

\mathbb{SOLUTION}:

Principal (P) = ₹ 450
Rate of interest (R) = 6% per annum
Time (T) = 8 months = \frac{8}{12} = \frac{2}{3} year

S.I = \frac{P \times R \times T}{100} \\ \\ S.I= \frac{450 \times 6 \times \frac{2}{3} }{100} \\ \\ S.I= \frac{450 \times 6 \times 2}{100 \times 3} \\ \\ S.I= 18

Now,
we know that,

Amount = Principal + S.I

Amount = 450 + 18

Amount = ₹ 468

Hence,
Hari payed ₹ 468 to his friend.

Steph0303: Perfect answer :)
BloomingBud: thank you :-)
Answered by ackshaineethakur
7

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