Question

1) Find the least number that is divisible by all the numbers between 1 and 10 (both
inclusive).
2) Find the least number which leaves a remainder 9 in each case when divided by 10, 16
and 24.
3) Find the smallest four-digit number which is completely divisible by 24, 25 and 60.
4)The LCM of two numbers is 6. If both the numbers are greater than one, find the
numbers.

Answer 1

The least number that is divisible by

(1,2,3,4,5,6,7,8,9,10)

we have to take LCM of given numbers.

As all number are divisible by 1, than

we neglect if

using prime factors

2=2, 3=3, 4=2×2, 5=5

6=2×3, 7=7, 8=2×2×2, 9=3×3, 10=2×5

Now LCM of given number is =2×2×2×3×3×5×7×

=8×9×35

LCM=2520

∴ 2520 is least number divisible by (1.....10) both inclusive.

Hope it helps Mark this as the Brainliest answer

Answer 2

Answer:

2520

Step-by-step explanation: