Question

1. Find the least number which when divided by 12 and 18, leaves no remainder.​

Answer 1

Answer:

36

Step-by-step explanation:

hope it helps

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Answer 2

Given :

• Find the least number which when divided by 12 and 18, leaves no remainder.

To Find :

• The number

Solution :

$\sf\purple{To\: find \:the \:least \:no. \:first \:find\: the \:LCM \:of }$

$\sf\purple{12\:nd'\: 18.}$

$\begin{array}{r|l}2&12 , 18\\ \cline{2-2}2&6 , 9\\ \cline{2-2}3&3 , 9\\ \cline{2-2} &1 , 3\\ \end{array}$

$\sf\dashrightarrow{12 , 18 = 2^2 × 3^2}$

$\sf\green{Hence,\: 36\: is\: the \:least \:number.}$