Question

(1) Find the least number which when
divided by 8, 12 and 20 leaves
remainder 5 in each case.​

Answer 1

✰✰|| Given ||✰✰

• no. from which least no. divided = 8, 12, 20

• remainder leaves in each case = 5

✰✰|| To Find ||✰✰

• least no. which when divided by 8,12 and 20 leaves remainder 5 in each case.

✪|| Solution ||✪

LCM of 8,12 and 20 = 120

Least number = LCM + 5

☛ Least number = 120 + 5

☛ Least number = 125

Your answer is 125

Answer 2

Given : -

• least number which when divided by 8, 12
• 20 leaves remainder 5 in each case.

To find : -

• Find the least number which when divided by 8, 12 and 20 leaves remainder 5 in each case.

Solution : -

LCM of 8 , 12, 20 = 120

least number : - LCM + 5

⠀⠀⠀⠀⠀⠀⠀⠀⠀= 120 + 5

⠀⠀⠀⠀⠀⠀⠀⠀⠀= 125

solution is the 125