1. Find the least number which will not leave a remainder when divided by 48, 60 and 72.
Answers
Answered by
1
Answer:
Such smallest number is multiple of 48, 60, 72, 108 and 140. So, 2160 leaves remainder 0 when divided by any of 48, 60, 72, 108 and 140. Reducing the number by 10 will result in shortfall by 10 leaving remainder quotient (divisor-10). Ans.: 2150.
Answered by
1
LCM(48,60,72)=720
Ans=720
Therefore,it is the least number that will divide 48,60,72 is 720
Hope this may help u
Like and comment
Ans=720
Therefore,it is the least number that will divide 48,60,72 is 720
Hope this may help u
Like and comment
Similar questions