Question

1. Find the length of tangent drawn to a circle with radius 8 cm from a
point 17 cm away from the centre of the circle.​

Answer 1

Answer:

Step-by-step explanation:

Draw a circle with centre O.

Such that AB is a tangent of the circle and OB is the radius of the circle = 8 cm. And join AO such that AO = 17 cm.

Now in triangle AOB.

AB = under root (AO)^2 - (OB)^2 cm.

= under root (17)^2 - (8)^2 cm.

= under root 289 - 64 cm.

= under root 225 cm.

= 15 cm. (...Ans....)

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Step-by-step explanation:

Answer 2

Step-by-step explanation:

let the center of circle be O.

and radius is A

So, radius of circle is OA = 8 cm

and let the point drawn from the external point to the centre of circle, OP= 17 cm

NOW we now that when a tangent drawn from an external point and lie on the circle make an angle of 90 degree with the radius

So, triangle OAP

BY PYTHAGORAS THEOREM

WE GET .,

APSQUARE = OP SQUARE -OA SQUARE

SO , AP SQUARE = 289 -64

AP = ROOT (225)

AP = 15cm