Question

1) Find the length of the diagonal AC.
A(-3,1)
B(4,1)
D(-3,-3)
C(4, -3)
IT'S A rectangle​

Answer 1

Answer:

√65 units

Step-by-step explanation:

Given that ABCD is a rectangle whose three vertices are A(-3,1),B(4,1),C(4,-3) and D(-3,-3).

To find out: The length of one of its diagonal.

AC and BD will be the two diagonals of the rectangle ABCD.

we using the distance formula.

We know that, the distance between two points A(x1,y1) and C(x2,y2) is

AC=√(x2-x1)^2+(y2-y1)^2

=√(4-(-3))^2+(-3-1)^2

=√(4+3)^2+(-3-1)^2

=√(7)^2+(-4)^2

=√(49)+(16)

=√(65)

=√65 units

Hence, the length of one of the diagonal AC of the rectangle ABCD is √65 units.