Question

1.
Find the length of the hypotenuse in the following right triangles.
a. AABC, where ZC = 90°, BC = 8 cm and CA = 6 cm.
b. APQR, where ZP = 90°, PQ = 3 cm and PR = 4 cm.
c. AXYZ, where _Y = 90°, XY = 5 cm and YZ = 12 cm.​

Answer 1

Answer:

By Pythagoras theorem we have

A²+B² = C²

a) 8²+6²=100 , c=10

b) 3²+4²=25,c=5

c)5²+12²=169, c=13

hope it helps....

Answer 2

Answer:

a= 10 b= 5 c= 13

Step-by-step explanation:

a. hypo^2 = s^2+s^2 ( s= side )

hypo^2= 8^2+6^2

hypo^2 = 64+36

hypo^2= 100

hypo = 10

b. hypo^2 = 3^2+4^2

hypo^2=9+16

hypo^2=25

hypo=5

c. hypo^2 = 5^2 +12^2

hypo^2 = 169

hypo = 13

MAY HELP U IF UNDERSTAND TRY TO DO IT ON UR OWN