Physics, asked by padaramanjula22, 5 months ago

1. Find the magnitude of pressure in Pascal of a force of 150 N that acts normally on an area of 0.25 m2​

Answers

Answered by Anonymous
47

QUESTION :-

  • 1. Find the magnitude of pressure in Pascal of a force of 150 N that acts normally on an area of \sf {0.25 m^2}.

GIVEN :-

  • The force applied is 150N.
  • And, applied on an area of \sf {0.25 m^2}.

TO FIND :-

  • The pressure exerted on the area = ??.

We know that,

 \sf{ \underline{ \boxed { \bigstar \mid \bf pressure =  \frac{force}{area} \mid { \bigstar}}}} \\  \sf \to \: pressure \:  =  \frac{150n}{0.25 {m}^{2} }  \\  \sf \to \: p =  \frac{150}{ \cancel{25}}  \times  \cancel{100 }\\  \sf \to \: p = 150 \times 4 \\ \bf { \underline { \fcolorbox{black}{lightgreen}{ \bf {  \:  p = 600 \: p.a \: \:  or \: \:  pascal \:\:\: ➝ans. }}}}

Hence,

  • Pressure exerted is 600 Pascal.

ADDITIONAL INFO

  • Pressure :-  \sf \: pressure \:  =  \frac{force}{area}
  • Area :-   \sf \: area \:  =  \frac{force}{pressure}
  • Force :- Area × pressure.
Answered by ArcaneAssassin
101

 \huge\sf { \dag Question }

Find the magnitude of pressure in pascal of a force of 150 N that acts normally on an area of 0.25 m^2.

 \huge\sf { \dag Solution }

  {\underline {\underline  {\rm {\red { Given }}}}}

  •  \sf\orange { F (Force \: applied) = 150N }

  •  \sf\orange {A ( Area) = 0.25{m}^{2} }

  {\underline {\underline  {\rm {\red { To \: find: }}}}}

  •  \sf { Pressure \: exerted }

  {\underline {\underline  {\rm {\red { Calculation: }}}}}

We know that,

 {\qquad {\underline {\underline  {\rm {\purple { Pressure = \dfrac{ Force}{Area} }}}}}}

 \sf { \qquad \leadsto P = \dfrac{150}{0.25}  }

 \sf { \qquad \leadsto P = \dfrac{150 \times \cancel { 100}^{\: \: 4}}{ \cancel {25}}  }

 \sf { \qquad \leadsto P = 150 \times 4 }

 \sf\red { \qquad \leadsto P = 600Pa \: Ans. }

________________________________

 \huge\sf { \dag Additional \: Information: }

Let's know more about pressure-

  • Pressure is the effect of force on a given area. Simply we can say that, Pressure is the force per unit area.

  •  {\underline {\underline  {\rm {\red { P = \dfrac{ F}{A} }}}}}

Where,

  • P = pressure
  • F = force
  • A = area

  • SI unit of force is Pascal.

  • In liquids pressure depends upon the depth ( height ) and the density of the liquid.

  • Liquid pressure is measured with nanometer

  • The force exerted by the atmosphere on unit are is called atmospheric pressure.

  • Atmospheric pressure is measured by barometer.

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