Math, asked by lavya1931, 10 months ago

1. Find the measure of each angle of a regular octagon.
2. Find the sum of interior angles of a 12 sided convex polygon. Also find the number of diagonals. What can you say about the sum of exterior angle of this polygon?



3. Find the number of sides of regular polygon, each of whose exterior angles measure is 45o.


4. Find the measure of each exterior angle of a regular polygon which has 12 sides.
please tell with step by step

Answers

Answered by seemachavi
3

Answer:

1. No.of sides=8

We know sumo f the internal angles is (n-2) x 180

So ,

(8-2) x 180=6 x 180= 1080°

Therefore each side measuring 1080/8=135°

2. sumof the interior angles = (n-2) x 180=12-2 x 180=10 x 180=1800°

No.of diagonals=n(n-3) /2=12( 12-3)/2=108/2=54

3. Exterior angle measure=45degree

360/exterior angle measure=no.of sides

so

360/45=8 sides

4. Each exterior angle= 360/no.of sides

360/12=30°

Hope it is helpful

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Answered by prajapatiroshni136
4

Answer:

i hope it is useful for you

thank you

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