1) find the minimum value of the
Function f(x) = log2 (x²-2x+5)
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Step-by-step explanation:
f(x)=x
2
+2x−5
f
′
(x)=2x+2
When x<−1,f
′
(x)<0
When x>−1,f
′
(x)>0
∴ For x>−1,f(x) is strictly increasing
∴(−1,∞)
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