Question

1. Find the mode and range of the following data: 3,5, 1,2,3,6,2.6.3. Solution​

Answer 1

Answer:

58

Step-by-step explanation:

a) Mean=

Total no. of observations

sum of the number

​

⇒ Mean=

40

2+3+4+3+5+5+6+7+8+9+6+6+5+3+13+7+8+8+2+9+11+7+8+4+5+45+48+60+42+53+47+51+54+49+48+47+53+48+44+46

​

⇒ Mean=

40

119+770

​

,

40

889

​

=22.2

∴ Mean=22.2

b) To arrange data in ascending order

Median : 2,2,3,3,3,4,4,5,5,5,5,6,6,6,7,7,7,8,8,8,8,9,9,11,13,42,44,45,46,47,48,48,49,51,53,53,54,60.

Median =

2

8+8

​

=

12

6

​

=8

c)

Mode :- The only number which appears multiple times

Mode =2,3,4,5,6,7,8,9,48,53

d) Range: The subtract the smallest number from the largest number

=60−2=58

∴ Range =58

Answer 2

Answer:

LETS FIND MODE :

ASCENDING ORDER: 1,2,2,3,3,3,5,6,6.

MODE IS 3, BECAUSE 3 OCCURS MORE THAN 2 TIMES.

NOW FIND MEDIAN:

ASCENDING ORDER: 1,2,2,3,3,3,5,6,6.

N =9. 9 IS ODD NO, SO USE FORMULA 1.

MEDIAN: 1+ N/2TH TERM.

1+9/2TH TERM.

10/2TH TERM.

5TH TERM.

MEDIAN IS :3.

find mean:

ARITHMETIC mean = sum of all observations/ no of all observations.

ARITHMETIC mean: 1,2,2,3,3,3,5,6,6/ 9

31/ 9 IS 3.44