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1) find the molarity of a 100 ml solution containing 60 gms of glucose ???
=> Class 9 ( ATOMS AND MOLECULES )
@ Prabhudutt....
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Answered by
5
☆☆AS-SALAMU-ALYKUM☆☆
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MOLARITY = NUMBER OF MOLES OF SOLUTE ÷ VOLUME OF SOLUTION
MOLES OF SOLUTE THAT IS GLUCOSE ARE = MASS÷ MOLAR MASS
MOLAR MASS OF GLUCOSE IS = C6H12O6=12×6 + 1×12 + 16 ×6 = 180g/mol
MOLES OF GLUCOSE = 60÷ 180= 1÷3= 0.333mol
VOLUME OF SOLUTION =100ml
1ml =1÷1000l
100ml=1÷1000 × 100
100ml= 0.1 lit
VOLUME OF SOLUTION =0.1 LITRE
NOW
MOLARITY = 0.333÷0.1
MOLARITY =3.33 M
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♡♤♡INSHALLAH IT WILL HELP U ♡♤♡
●●●●●●●●●●●●●●●●●●●●
HAVE A NICE DAY ☺☺
●●●●●●●●●●●●●●●●●●●●
MOLARITY = NUMBER OF MOLES OF SOLUTE ÷ VOLUME OF SOLUTION
MOLES OF SOLUTE THAT IS GLUCOSE ARE = MASS÷ MOLAR MASS
MOLAR MASS OF GLUCOSE IS = C6H12O6=12×6 + 1×12 + 16 ×6 = 180g/mol
MOLES OF GLUCOSE = 60÷ 180= 1÷3= 0.333mol
VOLUME OF SOLUTION =100ml
1ml =1÷1000l
100ml=1÷1000 × 100
100ml= 0.1 lit
VOLUME OF SOLUTION =0.1 LITRE
NOW
MOLARITY = 0.333÷0.1
MOLARITY =3.33 M
●●●●●●●●●●●●●●●●●●●●
♡♤♡INSHALLAH IT WILL HELP U ♡♤♡
●●●●●●●●●●●●●●●●●●●●
HAVE A NICE DAY ☺☺
Answered by
7
Moles of glucose : 0.33 mol
volume of solution : 100ml
volume of solution ( in litres) : 0.1 L
Molarity : 0.33 / 0.1 = 3.3 M
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