Question

1. Find the nature of roots of
1 point
quadratic equation, 3x^2 - 413
x+4=0.​

Answer 1

Step-by-step explanation:

D=b^2-4ac

a=3;b=-413;C=4

D=(3)^2-4(-413)(4)

D=9+6608

D=6617.

Hence D greater than zero.

It is real and unique roots

Answer 2

Answer:

3x²+ x + 4 - 413

3x²+ x - 409

a=3

b=1

c= - 409

D (Discriminant) = b² - 4ac

D= 1² - (4 ×3 × -409)

D= 1 + 4908

D = 4909

As D > 0

Hence roots of above quadratic equation would be real and distinct .

Hope you got it !