Question

1. Find the nature of the roots of the following quadratic equations. If the real roots exist,
find them:
(1) 3x^2 - 4√3x + 4= 0​

Answer 1

Answer:

Roots are : √3/2 and √3/2

Step-by-step explanation:

3x²- 4√3x + 4=0

here a=3,b=-4√3 and c=4

then b²-4ac

=(4√3)²-4*3*4

=48-48=0

so the roots are real and equal

Now

3x² - 4√3x + 4=0

(√3 x)²-2*2(√3x)+2²=0

(√3x-2)²=0

√3x-2=0

√3x=2

x=√3/2,√3/2